获取IP地址的方法:
import javax.servlet.http.HttpServletRequest;
/**
* 自定义访问对象工具类
*
* 获取对象的IP地址等信息
* @author X-rapido
*
*/
public class CusAccessObjectUtil {
/**
* 获取用户真实IP地址,不使用request.getRemoteAddr();的原因是有可能用户使用了代理软件方式避免真实IP地址,
*
* 可是,如果通过了多级反向代理的话,X-Forwarded-For的值并不止一个,而是一串IP值,究竟哪个才是真正的用户端的真实IP呢?
* 答案是取X-Forwarded-For中第一个非unknown的有效IP字符串。
*
* 如:X-Forwarded-For:192.168.1.110, 192.168.1.120, 192.168.1.130,
* 192.168.1.100
*
* 用户真实IP为: 192.168.1.110
*
* @param request
* @return
*/
public static String getIpAddress(HttpServletRequest request) {
String ip = request.getHeader("X-FORWARDED-FOR");
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("Proxy-Client-IP");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("WL-Proxy-Client-IP");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("HTTP_CLIENT_IP");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("HTTP_X_FORWARDED_FOR");
}
if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getRemoteAddr();
}
return ip;
}
}
获取端口的方法:
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String uri = request.getRequestURI();//返回请求行中的资源名称
String url = request.getRequestURL().toString();//获得客户端发送请求的完整url
String ip = request.getRemoteAddr();//返回发出请求的IP地址
String params = request.getQueryString();//返回请求行中的参数部分
String host=request.getRemoteHost();//返回发出请求的客户机的主机名
int port =request.getRemotePort();//返回发出请求的客户机的端口号。
System.out.println(ip);
System.out.println(url);
System.out.println(uri);
System.out.println(params);
System.out.println(host);
System.out.println(port);
}
最新评论
网飞没问题, 迪士尼+有解决方案么?
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已解决
这样的话数据库里的结构为{"attachment":{"content":"xxx"}}, 要怎么才能变成{"content":"xxx"},从而使结构保持一致?
赞! make test不过的坑都写到的,谢谢楼主~
谢谢你
用了root用户还是一直502是怎么回事呢
student id 是空的